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• Statistical Inference 统计推断
• Statistical Computing 统计计算
• (Generalized) Linear Models 广义线性模型
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• Foundations of Data Science 数据科学基础

## 物理代写|流体力学代写Fluid Mechanics代考|Balance of Energy

The conservation law of energy in integral form, which we discuss in the following sections, is based on the thermodynamic principals, primarily the first law of thermodynamics for open systems and time independent control volumes. It is fully independent of the conservation law of energy derived for fluid mechanics. How-ever, it implicitly contains the irreversibility aspects described by the dissipation process in the previous chapter. The contribution of the irreversibility is explicitly expressed by using the Clausius-Gibbs entropy equation, known as the second law of thermodynamics. The energy equation is applied to a variety of engineering devices such as internal combustion engines, jet engines, steam and gas turbine engines and their components in which a chain of energy conversion processes takes place. As an example, Fig. $5.9$ shows a high performance gas turbine engine with several components to which we apply the results of our derivations.

In this chapter, we apply the conservation law of energy to a material volume with a system boundary that moves through the space where it may undergo deformation, rotation, and translation. The first law of thermodynamics in integral form states that if we add thermal energy (heat) $Q$ and mechanical energy (work) $W$ to a closed system, the total energy of the system $E$ experiences a change from initial state $E_1$ to the final state $E_2$. Expressing in terms of energy balance, we have:
$$Q+W=E_2-E_1 .$$
The total energy $E$ is the sum of internal, kinetic and potential energies,
$$E=U+\frac{1}{2} m V^2+m g z$$

## 物理代写|流体力学代写Fluid Mechanics代考|Steady Flow, Constant Mass Flow

In many applications, the mass flow remains constant from the inlet to the exit of the machine. Examples are uncooled turbines and compressors where no mass flow is added during the compression or expansion process. In this case, Eq. (5.82) reduces to:
$$\dot{Q}+\dot{W}{\text {Shaft }}=\dot{m}\left[\left(h+\frac{1}{2} V^2+g z\right){\text {out }}-\left(h+\frac{1}{2} V^2+g z\right){\text {in }}\right] .$$ Now, we define the specific total enthalpy $$H \equiv h+\frac{1}{2} V^2+g z$$ and insert it into Eq. (5.83), from which we get: $$\dot{Q}+\dot{W}{\text {Shaft }}=\dot{m}\left(H_{\text {out }}-H_{\text {in }}\right) .$$
In Eqs. (5.83) or (5.85), the contribution of $\Delta g z$ compared to $\Delta h$ and $\Delta V^2 / 2$ is negligibly small. Using the above equation, the energy balance for the major components of the gas turbine engine shown in Fig. $5.9$ can be established as detailed in the following section.

# 力学代考

## 物理代写|流体力学代写Fluid Mechanics代考|Balance of Energy

$$Q+W=E_2-E_1 .$$

$$E=U+\frac{1}{2} m V^2+m g z$$

## 物理代写|流体力学代写Fluid Mechanics代考|Steady Flow, Constant Mass Flow

$$\dot{Q}+\dot{W} \text { Shaft }=\dot{m}\left[\left(h+\frac{1}{2} V^2+g z\right) \text { out }-\left(h+\frac{1}{2} V^2+g z\right) \text { in }\right]$$

$$H \equiv h+\frac{1}{2} V^2+g z$$

$$\dot{Q}+\dot{W} \text { Shaft }=\dot{m}\left(H_{\text {out }}-H_{\text {in }}\right) .$$

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## MATLAB代写

MATLAB 是一种用于技术计算的高性能语言。它将计算、可视化和编程集成在一个易于使用的环境中，其中问题和解决方案以熟悉的数学符号表示。典型用途包括：数学和计算算法开发建模、仿真和原型制作数据分析、探索和可视化科学和工程图形应用程序开发，包括图形用户界面构建MATLAB 是一个交互式系统，其基本数据元素是一个不需要维度的数组。这使您可以解决许多技术计算问题，尤其是那些具有矩阵和向量公式的问题，而只需用 C 或 Fortran 等标量非交互式语言编写程序所需的时间的一小部分。MATLAB 名称代表矩阵实验室。MATLAB 最初的编写目的是提供对由 LINPACK 和 EISPACK 项目开发的矩阵软件的轻松访问，这两个项目共同代表了矩阵计算软件的最新技术。MATLAB 经过多年的发展，得到了许多用户的投入。在大学环境中，它是数学、工程和科学入门和高级课程的标准教学工具。在工业领域，MATLAB 是高效研究、开发和分析的首选工具。MATLAB 具有一系列称为工具箱的特定于应用程序的解决方案。对于大多数 MATLAB 用户来说非常重要，工具箱允许您学习应用专业技术。工具箱是 MATLAB 函数（M 文件）的综合集合，可扩展 MATLAB 环境以解决特定类别的问题。可用工具箱的领域包括信号处理、控制系统、神经网络、模糊逻辑、小波、仿真等。

assignmentutor™您的专属作业导师
assignmentutor™您的专属作业导师